Anyone good at Math?
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Anyone good at Math?
I have a problem on my homework, does anyone know how to do this?
How to solve (x^2-3)^2+2?
I did the math and got x^4-4 and my program is telling me the correct answer is x^4-6x^2+11. What the hell am I doing wrong?
How to solve (x^2-3)^2+2?
I did the math and got x^4-4 and my program is telling me the correct answer is x^4-6x^2+11. What the hell am I doing wrong?
Vampire_of_Death- Harlequin of Hate
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Re: Anyone good at Math?
That IS a caret? Like x^2=x*x, right? Like squared.
You should be powering x to (2-3), then powering THAT to (2+2), if I'm correct.
You should be powering x to (2-3), then powering THAT to (2+2), if I'm correct.
Rapsheba555- Weegee
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Re: Anyone good at Math?
It has a squared binomial: (x^2-3)^2=x^4-6x^2+9 so the result is that, plus 2, which is certainly: x^4-6x^2+11
You know.. because of the (a+b)^2=a^2+2ab+b^2 thing =)
You know.. because of the (a+b)^2=a^2+2ab+b^2 thing =)
aninyosaloh- The Shadow In The Night
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Re: Anyone good at Math?
that's what I thought, but i wasn't totally sure.
Rapsheba555- Weegee
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Re: Anyone good at Math?
o3o *is in algebra 1*
WtF?
WtF?
ZombieData- Emo Dude
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Re: Anyone good at Math?
You'll get to it.
Rapsheba555- Weegee
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Re: Anyone good at Math?
I always used to just give up and stick some real numbers in where the "literature" was.
Ghost- Local Figment of the Imagination
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Re: Anyone good at Math?
lol, "literature"
Rapsheba555- Weegee
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Re: Anyone good at Math?
Thanks guys, I figured I had to do the FOIL things, so thanks!
Vampire_of_Death- Harlequin of Hate
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Re: Anyone good at Math?
Ah foil. First outer inner last.
Rapsheba555- Weegee
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Re: Anyone good at Math?
I know, all it said was solve, simple instructions lead to fail. I just tried everything that I could until I got it. In case anyone is interested, this is how its done.
(x^2-3)^2 = x^4 - 6x^2 + 9
x^4 - 6x^2 + 9 + 2 = x^4 - 6x^2 + 11
(x^2-3)^2. "^2" means to square what's in the parenthesis. To square means to multiply twice So "(x^2-3)^2" equals (x^2-3)(x^2-3) which means you have to FOIL that.
(x^2-3)(x^2-3) = x^4 - 6x^2 + 9
now all you have to do is add the 2 to the 9;
x^4 - 6x^2 + 9 + 2 = x^4 - 6x^2 + 11
x^4 - 6x^2 + 11 is the answer
(x^2-3)^2 = x^4 - 6x^2 + 9
x^4 - 6x^2 + 9 + 2 = x^4 - 6x^2 + 11
(x^2-3)^2. "^2" means to square what's in the parenthesis. To square means to multiply twice So "(x^2-3)^2" equals (x^2-3)(x^2-3) which means you have to FOIL that.
(x^2-3)(x^2-3) = x^4 - 6x^2 + 9
now all you have to do is add the 2 to the 9;
x^4 - 6x^2 + 9 + 2 = x^4 - 6x^2 + 11
x^4 - 6x^2 + 11 is the answer
Vampire_of_Death- Harlequin of Hate
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Re: Anyone good at Math?
yep. Exactly what I thought. It's like the caret in the TI-83s. I was just too lazy to actually write it all out and see how it actually panned out.
Rapsheba555- Weegee
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