Anyone good at Math?

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Anyone good at Math?

Post by Vampire_of_Death on October 16th 2009, 10:19 am

I have a problem on my homework, does anyone know how to do this?

How to solve (x^2-3)^2+2?
I did the math and got x^4-4 and my program is telling me the correct answer is x^4-6x^2+11. What the hell am I doing wrong?

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Re: Anyone good at Math?

Post by Rapsheba555 on October 16th 2009, 4:05 pm

That IS a caret? Like x^2=x*x, right? Like squared.

You should be powering x to (2-3), then powering THAT to (2+2), if I'm correct.

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Re: Anyone good at Math?

Post by aninyosaloh on October 17th 2009, 6:47 am

It has a squared binomial: (x^2-3)^2=x^4-6x^2+9 so the result is that, plus 2, which is certainly: x^4-6x^2+11

You know.. because of the (a+b)^2=a^2+2ab+b^2 thing =)

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Re: Anyone good at Math?

Post by Rapsheba555 on October 17th 2009, 7:43 pm

that's what I thought, but i wasn't totally sure.

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Re: Anyone good at Math?

Post by ZombieData on October 17th 2009, 7:52 pm

o3o *is in algebra 1*


WtF?

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Re: Anyone good at Math?

Post by Rapsheba555 on October 17th 2009, 7:54 pm

You'll get to it.

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Re: Anyone good at Math?

Post by Ghost on October 18th 2009, 6:15 am

I always used to just give up and stick some real numbers in where the "literature" was. Lol

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Re: Anyone good at Math?

Post by Rapsheba555 on October 18th 2009, 1:26 pm

lol, "literature"

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Re: Anyone good at Math?

Post by Vampire_of_Death on October 20th 2009, 9:02 pm

Thanks guys, I figured I had to do the FOIL things, so thanks!

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Re: Anyone good at Math?

Post by Rapsheba555 on October 20th 2009, 9:04 pm

Ah foil. First outer inner last.

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Re: Anyone good at Math?

Post by Vampire_of_Death on October 20th 2009, 9:15 pm

I know, all it said was solve, simple instructions lead to fail. I just tried everything that I could until I got it. In case anyone is interested, this is how its done.


(x^2-3)^2 = x^4 - 6x^2 + 9

x^4 - 6x^2 + 9 + 2 = x^4 - 6x^2 + 11


(x^2-3)^2. "^2" means to square what's in the parenthesis. To square means to multiply twice So "(x^2-3)^2" equals (x^2-3)(x^2-3) which means you have to FOIL that.

(x^2-3)(x^2-3) = x^4 - 6x^2 + 9

now all you have to do is add the 2 to the 9;

x^4 - 6x^2 + 9 + 2 = x^4 - 6x^2 + 11

x^4 - 6x^2 + 11 is the answer

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Re: Anyone good at Math?

Post by Rapsheba555 on October 20th 2009, 10:22 pm

yep. Exactly what I thought. It's like the caret in the TI-83s. I was just too lazy to actually write it all out and see how it actually panned out. :P

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